Find next palindrome in Python with Eaglesoft Programmers.

def next_palindrome(n):

    n=n+1

    while not is_palindrome(n):

        n += 1

    return n

def is_palindrome(n):

    return str(n)==str(n)[::-1]

if __name__ == "__main__":

    n=int(input("Enter the number of casese\n"))

    numbers=[]

    for i in range(n):

        number=int(input("Enter the number of that you want to find next palindrom\n"))

        numbers.append(number)

    for i in range(n):

        print(f"Next palindrome of {numbers[i]} is {next_palindrome(numbers[i])}")